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Vector spaces, subspaces and linear independence

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What a vector space is

Definition. A vector space over the real numbers is a set VV with two operations, vector addition and multiplication by a scalar, satisfying these rules for all u,v,w∈Vu, v, w \in V and scalars a,ba, b:

  1. Closure: u+v∈Vu + v \in V and au∈Va u \in V.
  2. Addition is commutative and associative.
  3. There is a zero vector: v+0=vv + 0 = v.
  4. Every vv has a negative: v+(−v)=0v + (-v) = 0.
  5. a(u+v)=au+ava(u + v) = au + av, (a+b)v=av+bv(a + b)v = av + bv, a(bv)=(ab)va(bv) = (ab)v, and 1v=v1v = v.

Examples.

  • Rn\mathbb{R}^n, the column vectors with nn real entries.
  • PnP_n, the polynomials of degree at most nn, such as 3−x+2x23 - x + 2x^2 in P2P_2.
  • Mm×nM_{m \times n}, the m×nm \times n real matrices.
  • The continuous functions on [0,1][0, 1].
  • The solutions of a homogeneous system Ax=0Ax = 0.

Non-examples.

  • The polynomials of degree exactly 2. Adding x2x^2 and −x2+x-x^2 + x gives xx, which has degree 1, so the set is not closed under addition.
  • The vectors in R2\mathbb{R}^2 with x≥0x \ge 0. Multiplying by −1-1 leaves the set.
  • The solutions of Ax=bAx = b with b≠0b \ne 0. The zero vector is not a solution.

Subspaces

Definition. A subset WW of a vector space VV is a subspace if it is a vector space with the same operations.

Subspace test. It is enough to check three things:

  1. 0∈W0 \in W.
  2. u,v∈W⇒u+v∈Wu, v \in W \Rightarrow u + v \in W.
  3. v∈W⇒av∈Wv \in W \Rightarrow a v \in W for every scalar aa.

The last two combine into one check: au+bv∈Wau + bv \in W for all u,v∈Wu, v \in W and all scalars a,ba, b.

Exam point. A quick way to rule a set out is that it does not contain 00. Every subspace of R3\mathbb{R}^3 is one of four kinds: {0}\{0\}, a line through the origin, a plane through the origin, or R3\mathbb{R}^3 itself.

Solved examples

Example 1. Which of these are subspaces of R3\mathbb{R}^3?

  • (a) {(x,y,z):x+2y−z=0}\{(x, y, z) : x + 2y - z = 0\}. Yes. It is a plane through the origin, the null space of [1 2 −1][1\ 2\ {-1}].
  • (b) {(x,y,z):x+y=1}\{(x, y, z) : x + y = 1\}. No. It does not contain 0.
  • (c) {(x,y,z):xy=0}\{(x, y, z) : xy = 0\}. No. It contains (1,0,0)(1, 0, 0) and (0,1,0)(0, 1, 0), but not their sum (1,1,0)(1, 1, 0). It is the union of two planes.
  • (d) {(t,2t,−t):t∈R}\{(t, 2t, -t) : t \in \mathbb{R}\}. Yes. It is a line through the origin.
  • (e) {(x,y,z):x≥0}\{(x, y, z) : x \ge 0\}. No. It is not closed under multiplying by −1-1.

Example 2. Is the set of 2×22 \times 2 matrices with trace 0 a subspace of M2×2M_{2 \times 2}? Yes. The trace is linear: tr⁡(aA+bB)=atr⁡A+btr⁡B=0\operatorname{tr}(aA + bB) = a\operatorname{tr}A + b\operatorname{tr}B = 0. The set of invertible matrices is not a subspace: it does not contain the zero matrix, and I+(−I)=0I + (-I) = 0 is not invertible.

Unions and intersections.

  • The intersection of two subspaces is always a subspace.
  • A union of two subspaces is a subspace only if one contains the other.
  • The sum U+W={u+w:u∈U,w∈W}U + W = \{u + w : u \in U, w \in W\} is the smallest subspace containing both.

Linear combinations and span

A linear combination of v1,…,vkv_1, \dots, v_k is c1v1+⋯+ckvkc_1 v_1 + \dots + c_k v_k. Their span is the set of all linear combinations, and it is always a subspace.

Example 3: is a vector in the span? Is (3,5,7)(3, 5, 7) in span⁡{(1,1,1),(1,2,3)}\operatorname{span}\{(1, 1, 1), (1, 2, 3)\}? We need a(1,1,1)+b(1,2,3)=(3,5,7)a(1, 1, 1) + b(1, 2, 3) = (3, 5, 7):

  • a+b=3a + b = 3;
  • a+2b=5a + 2b = 5;
  • a+3b=7a + 3b = 7.

The first two give b=2b = 2 and a=1a = 1. The third then gives 1+6=71 + 6 = 7, which holds. Yes: (3,5,7)=(1,1,1)+2(1,2,3)(3, 5, 7) = (1, 1, 1) + 2(1, 2, 3).

Matrix view. bb is in the span of the columns of AA exactly when Ax=bAx = b has a solution, that is, when rank⁡[A∣b]=rank⁡A\operatorname{rank}[A \mid b] = \operatorname{rank} A.

Linear independence

Definition. Vectors v1,…,vkv_1, \dots, v_k are linearly independent if

c1v1+⋯+ckvk=0  ⟹  c1=⋯=ck=0.c_1 v_1 + \dots + c_k v_k = 0 \implies c_1 = \dots = c_k = 0 .

Otherwise they are dependent, and at least one of them is a combination of the others.

Tests.

  • Put the vectors as the columns of a matrix AA. They are independent exactly when rank⁡A=k\operatorname{rank} A = k, that is, when Ax=0Ax = 0 has only the zero solution.
  • nn vectors in Rn\mathbb{R}^n are independent exactly when det⁡A≠0\det A \ne 0.
  • More than nn vectors in Rn\mathbb{R}^n are always dependent.
  • Any set containing the zero vector is dependent.
  • Two vectors are dependent exactly when one is a multiple of the other.

Solved examples

Example 4. Are (1,2,3)(1, 2, 3), (4,5,6)(4, 5, 6) and (7,8,9)(7, 8, 9) independent?

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